a64l(3C)

NAME

a64l(), l64a() − convert between long integer and base-64 ASCII string

SYNOPSIS

#include <stdlib.h>

long int a64l(const char *s);

char *l64a(long int l);

DESCRIPTION

These functions are used to maintain numbers stored in base-64 ASCII characters. This is a notation by which long integers can be represented by up to six characters; each character represents a "digit" in a radix-64 notation.

The characters used to represent "digits" are . for 0, / for 1, 0 through 9 for 2−11, A through Z for 12−37, and a through z for 38−63.

The leftmost character is the least significant digit. For example,

a0 = (38 x 640) + (2 x 641) = 166

a64l() takes a pointer to a null-terminated base-64 representation and returns a corresponding long value. If the string pointed to by s contains more than six characters, a64l() uses the first six.

l64a() takes a long argument and returns a pointer to the corresponding base-64 representation. If the argument is 0, l64a() returns a pointer to a null string.

WARNINGS

The value returned by l64a() is a pointer into a static buffer, the contents of which are overwritten by each call.

STANDARDS CONFORMANCE

a64l(): SVID2

l64a(): SVID2