expr(1) — Commands
NAME
expr − Evaluates arguments as expressions
SYNOPSIS
expr expression
DESCRIPTION
The expr command reads an expression, evaluates it, and writes the result to standard output. Within the expression argument, you must separate each term with spaces, precede characters special to the shell with a \ (backslash), and quote strings containing spaces or other special characters. Note that expr returns 0 to indicate a zero value, rather than the null string. Integers can be preceded by a unary minus sign. Internally, integers are treated as 64-bit or 32-bit two’s complement numbers, depending on the word size of the hardware platform.
The operators and keywords are described in the following listing. Characters that need to be escaped are preceded by a \ (backslash). The list is in order of increasing precedence with equal precedence operators grouped within {} (braces).
expression1 \| expression2
Returns expression1 if it is neither null nor 0 (zero); otherwise, returns expression2.
expression1 \& expression2
Returns expression1 if neither expression1 nor expression2 is null nor 0; otherwise, returns 0.
expression1 { =, \>, \>=, \<, \<=, != } expression2
Returns the result of an integer comparison if both expressions are integers; otherwise, returns the result of a string comparison.
expression1 {+, - } expression2
Adds or subtracts integer-valued arguments.
expression1 { \∗, /, % } expression2
Multiplies, divides, or provides the remainder from the division of integer-valued arguments.
expression1 : expression2 or match expression1 expression2
Compares expression1 with expression2, which must be a regular expression, with syntax as described for grep, except that all patterns are anchored, so ^ (circumflex) (which anchors a pattern to the beginning of a line) is not a special character in this context.
Normally, the matching operator returns the number of characters matched. Alternatively, you can use the \(...\) symbols in expression2 to return a portion of expression1.
(expression)
Provides expression grouping.
To avoid unpredictable results when using a range expression to match a class of characters, use a character class expression rather than a standard range expression. For information about character class expressions, see the discussion of this topic included in the description of the grep command.
FUNCTIONS
The expr command provides the following string-expression functions. Strings containing white space must be quoted. The first character of a string is position 1. The information returned by all of these functions is in the form of a string:
index string1 string2
Compares each character in the second string against each character in the first string and returns the position in the first string of the first match found, where the first match is the match closest to the beginning of string1.
length string
Returns the length of the string argument.
match string1 string2
See the description of the : (colon) match operator, above.
substr string start length
Returns the substring of string that begins at character position start and is length characters long.
EXAMPLES
1.To increment a shell variable, enter:
COUNT=‘expr $COUNT + 1‘
This adds 1 to the COUNT shell variable (see sh for details).
2.To find the length of a shell variable, enter:
RES=‘expr "$VAR" : ".∗"‘
Note that VAR is in double quotes to avoid problems where VAR is NULL or contains embedded spaces. The regular expression is also quoted to avoid expansion by the shell. This operation can also be performed as:
RES=‘expr length "$VAR"‘
3.To use part of a shell variable, enter:
RES=‘expr "$VAR" : "-∗\(.∗\)"‘
This removes leading - (dashes), if any, from VAR. If the \( \) characters were omitted, RES would contain the length of VAR.
4.To find a character from one string in another string, enter:
INDEX=‘expr index "Hello World!" "Wo"‘
Note that the returned value is 5, not 7. The first match is the fifth character in string1, matching the o in string2 rather than the W, which is the seventh character in string1.
5.Special considerations:
RES=‘expr "x$VAR" : "x-∗\(.∗\)"‘
This succeeds even if VAR has the value - (dash).
RES=‘expr "x$VAR" = "x="
This succeeds even if VAR has the value = (equal sign).
EXIT VALUES
The expr command returns the following exit values:
0The expression is neither null nor 0.
1The expression is null or 0.
2The expression is invalid.